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(F)=12F^2-7F-10
We move all terms to the left:
(F)-(12F^2-7F-10)=0
We get rid of parentheses
-12F^2+F+7F+10=0
We add all the numbers together, and all the variables
-12F^2+8F+10=0
a = -12; b = 8; c = +10;
Δ = b2-4ac
Δ = 82-4·(-12)·10
Δ = 544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{544}=\sqrt{16*34}=\sqrt{16}*\sqrt{34}=4\sqrt{34}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{34}}{2*-12}=\frac{-8-4\sqrt{34}}{-24} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{34}}{2*-12}=\frac{-8+4\sqrt{34}}{-24} $
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